1.
Jawab:
Tanpa VLSM
Jumlah host terbesar = 28 hosts = 5 bit (karena 2^5 = 32)
Jumlah subnet = 5 = 3 bit (karena 2^3 = 8)
5 bit + 3 bit = 8 bit ---> cocok
Subnet Mask yang akan dipakai (natural mask diperluas 3 bit) = 255.255.255.(128+64+32)
= 255.255.255.224 atau /27
netA: 204.15.5.0 /27
netB: 204.15.5.32/27
netC: 204.15.5.64/27
netD: 204.15.5.96/27
netE: 204.15.5.128/27
Dengan VLSM
netB: 204.15.5.0 255.255.255.224
netE: 204.15.5.32 255.255.255.224
netA: 204.15.5.64 255.255.255.240
netD: 204.15.5.80 255.255.255.240
netC: 204.15.5.96 255.255.255.252
http://www.4shared.com/file/ZMSq5Zm3ba/subnetting_excercise1.html
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