Viva le Blog!

Sunday, 29 March 2015

Memahami science dari sudut memahami perilakunya. Baru kalau ada meteran dan waktu, diukur berapa lama reaksi ini terjadi lengkap (complete) jika diberi aksi sesuatu.

Misalnya kalau diberi ini jadi begini. Filosofi ini juga terdaftar di hukum newton ketiga: "Ada aksi ada reaksi".

Thursday, 26 March 2015

Small Basic: Program that interupt

This the example of sub that interrupt the main loop i.e. main program:


'maincode 

GraphicsWindow.MouseDown = mousclick  



For i = 0 to 10000000000

  TextWindow.WriteLine("Hello")

  Program.delay(1000)

endfor



sub mousclick

if Mouse.IsLeftButtonDown = "true" then

Program.End()

endif

endsub

1. Rangka
Seperti halnya rangka html:
<html>
<head>
</head>
<body>
Tulisan-tulisan halaman web / content ditambahkan disini.
</body>
</html>

assembly juga punya rangka:
.code

.segment

.data

2. Untuk mengkompile file assembly (.asm) membutuhkan
Alurkerjanya: .asm > .obj > .com atau .exe

Tugas register SI DI memegang peranan penting dalam operasi pada string.
Register CX untuk counter pada looping

Tampilan debug

Tampilan memori komputer (menggunakan debug command di shell windows "debug filekamu.com dan -d"):

Properti file program .asm kamu:
1. Jumlah segmen
2.

Alamat-alamat memory
B800h:0000

Wednesday, 25 March 2015

communicative
A +B

associative
as long its add

excercise 1:
A + AB = A

ex 2:
(AB)(BC)

Industry
1. Communication/Information technology
2. Electronics
3. Machinery/Car/Chemical
4. Medical
5. Construction/Real Estate
6. Food
7. Consumer goods/Apparel
8. Speciality trading
9. General trading company
10. Retail/logistics
11. Banking
12. Insurance
13. Securities
14. Other financial
15. Publishing/Media
16. Hospitality/

In each industry there are below position:
1.
2.
3.
4.
5.

Tuesday, 24 March 2015

Purpose:
To get rid of the unnecessary.
To get the connection between or

Problems:
Below is the seed problem of two variables from which we can derive the algorithm.

Problem 1. AB + A + B
Solving:
1. AB + A + B
2. (AB + A) + B ; adding parantheses
3. A . (B + 1) + B ; look for a
4. A . 1 + B ; (B+1) is equal to 1
5. A + B ; Done /Finish

Problem 2. AB + A
Solving:
1. A.B + A
2. A(B+1)
3. A.1
4. A

Problem 1. A OR A or in other case:
A + A
Solving:
1. I build truth table to solve this.
A A OUT
0 0 0
1 1 1

2. Conclude that OUT is the same value with A, so, A + A is equal to A.

Problem 0. AB + AB
Solve:
1. AB + AB
2. A(B+B)
3. AB